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Standard Normal Distribution and Z-Table

Foundations of StatisticsProbability Distributions🟒 Free Lesson

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Standard Normal Distribution and Z-Table

Foundations of Statistics

The Universal Reference Distribution

The standard normal transforms any normal distribution into a common scale, enabling probability calculations across diverse contexts. Mastering Z-tables and Z-scores is essential for hypothesis testing, confidence intervals, and comparing across different datasets.

  • Medical Diagnostics β€” Z-scores help identify abnormal lab results by comparing to reference populations
  • Manufacturing β€” Standardized measurements enable quality control across different production lines
  • Education β€” Standardized tests use Z-scores to compare performance across different test versions

The Z-distribution is the Rosetta Stone of statistical inference.


Core Concepts

The standard normal distribution Z∼N(0,1)Z \sim N(0, 1) is the reference distribution for all normal probability calculations. Its ubiquity stems from the Central Limit Theorem: regardless of the underlying distribution, standardized sums converge to N(0,1)N(0,1).

DfStandard Normal

The standard normal random variable ZZ has pdf:

Ο•(z)=12Ο€eβˆ’z2/2,z∈R\phi(z) = \frac{1}{\sqrt{2\pi}} e^{-z^2/2}, \quad z \in \mathbb{R}

Any normal X∼N(ΞΌ,Οƒ2)X \sim N(\mu, \sigma^2) can be standardized via Z=(Xβˆ’ΞΌ)/ΟƒβˆΌN(0,1)Z = (X - \mu)/\sigma \sim N(0,1).

Standard Normal PDF

Ο•(z)=12Ο€eβˆ’z2/2\phi(z) = \frac{1}{\sqrt{2\pi}} e^{-z^2/2}

Here,

  • Ο•(z)\phi(z)=Standard normal PDF
  • zz=Standard score (number of SDs from mean)

Derivation: Why βˆ«βˆ’βˆžβˆžeβˆ’z2/2 dz=2Ο€\int_{-\infty}^{\infty} e^{-z^2/2} \, dz = \sqrt{2\pi}

ThNormalization Constant of the Gaussian

We must show βˆ«βˆ’βˆžβˆžeβˆ’z2/2 dz=2Ο€\int_{-\infty}^{\infty} e^{-z^2/2} \, dz = \sqrt{2\pi}.

Proof (polar coordinates trick): Let I=βˆ«βˆ’βˆžβˆžeβˆ’z2/2 dzI = \int_{-\infty}^{\infty} e^{-z^2/2} \, dz. Then:

I2=βˆ«βˆ’βˆžβˆžβˆ«βˆ’βˆžβˆžeβˆ’(x2+y2)/2 dx dyI^2 = \int_{-\infty}^{\infty} \int_{-\infty}^{\infty} e^{-(x^2+y^2)/2} \, dx \, dy

Switch to polar coordinates (r,ΞΈ)(r, \theta): x2+y2=r2x^2 + y^2 = r^2, dx dy=r dr dΞΈdx\,dy = r\,dr\,d\theta:

I2=∫02Ο€βˆ«0∞eβˆ’r2/2 r dr dΞΈ=2Ο€βˆ«0∞r eβˆ’r2/2 drI^2 = \int_0^{2\pi} \int_0^{\infty} e^{-r^2/2} \, r \, dr \, d\theta = 2\pi \int_0^{\infty} r \, e^{-r^2/2} \, dr

Substitute u=r2/2u = r^2/2, du=r drdu = r\,dr:

I2=2Ο€βˆ«0∞eβˆ’u du=2Ο€β‹…1=2Ο€β€…β€ŠβŸΉβ€…β€ŠI=2Ο€I^2 = 2\pi \int_0^{\infty} e^{-u} \, du = 2\pi \cdot 1 = 2\pi \implies I = \sqrt{2\pi}

Key Properties

ThMoments of the Standard Normal

For Z∼N(0,1)Z \sim N(0,1):

E[Z]=0,Var(Z)=1E[Z] = 0, \quad \text{Var}(Z) = 1

All odd central moments vanish by symmetry: E[Z2k+1]=0E[Z^{2k+1}] = 0.

The even moments are: E[Z2k]=(2k)!2kβ‹…k!=(2kβˆ’1)!!E[Z^{2k}] = \frac{(2k)!}{2^k \cdot k!} = (2k-1)!!

In particular: E[Z2]=1E[Z^2] = 1, E[Z4]=3E[Z^4] = 3, E[Z6]=15E[Z^6] = 15.

Why the 4th Moment Matters

The excess kurtosis of the standard normal is ΞΊ=E[Z4]βˆ’3=0\kappa = E[Z^4] - 3 = 0. This is why the normal is called "mesokurtic." Distributions with ΞΊ>0\kappa > 0 are leptokurtic (heavy tails); ΞΊ<0\kappa < 0 are platykurtic (light tails).

MGF and CGF of the Standard Normal

MZ(t)=et2/2,KZ(t)=t22M_Z(t) = e^{t^2/2}, \quad K_Z(t) = \frac{t^2}{2}

Here,

  • MZ(t)M_Z(t)=Moment generating function
  • KZ(t)K_Z(t)=Cumulant generating function

Symmetry and the CDF

The standard normal satisfies Ξ¦(βˆ’z)=1βˆ’Ξ¦(z)\Phi(-z) = 1 - \Phi(z), so only positive zz-values need be tabulated. Also, Ξ¦(z)\Phi(z) has no closed form β€” it requires numerical integration or lookup tables.


The Z-Table

Using the Z-Table

The Z-table gives Ξ¦(z)=P(Z≀z)\Phi(z) = P(Z \leq z). Key identities:

  • P(Z>z)=1βˆ’Ξ¦(z)P(Z > z) = 1 - \Phi(z)
  • P(a<Z<b)=Ξ¦(b)βˆ’Ξ¦(a)P(a < Z < b) = \Phi(b) - \Phi(a)
  • P(∣Z∣<z)=2Ξ¦(z)βˆ’1P(|Z| < z) = 2\Phi(z) - 1

Common Critical Values

z0.05=1.645,z0.025=1.96,z0.01=2.326,z0.005=2.576z_{0.05} = 1.645, \quad z_{0.025} = 1.96, \quad z_{0.01} = 2.326, \quad z_{0.005} = 2.576

Here,

  • zΞ±z_{\alpha}=Critical value such that P(Z > z_Ξ±) = Ξ±
  • 1.961.96=For 95% confidence (two-sided)
  • 2.5762.576=For 99% confidence (two-sided)

Worked Example: Z-Score Calculation

Example: Height Distribution

Suppose adult male heights are X∼N(ΞΌ=70,Οƒ2=9)X \sim N(\mu = 70, \sigma^2 = 9) inches (so Οƒ=3\sigma = 3). Find P(X>76)P(X > 76).

Step 1: Standardize: Z=Xβˆ’703Z = \frac{X - 70}{3}

Step 2: P(X>76)=P(Z>76βˆ’703)=P(Z>2)=1βˆ’Ξ¦(2)P(X > 76) = P\left(Z > \frac{76 - 70}{3}\right) = P(Z > 2) = 1 - \Phi(2)

Step 3: From the Z-table: Ξ¦(2)=0.9772\Phi(2) = 0.9772

Step 4: P(X>76)=1βˆ’0.9772=0.0228P(X > 76) = 1 - 0.9772 = 0.0228

So approximately 2.28%2.28\% of men are taller than 76 inches.


Connection to the Central Limit Theorem

ThCLT and the Standard Normal

Let X1,X2,…X_1, X_2, \ldots be i.i.d. with mean ΞΌ\mu and variance Οƒ2>0\sigma^2 > 0. Then:

XΛ‰nβˆ’ΞΌΟƒ/nβ†’dN(0,1)asΒ nβ†’βˆž\frac{\bar{X}_n - \mu}{\sigma / \sqrt{n}} \xrightarrow{d} N(0, 1) \quad \text{as } n \to \infty

This is why the standard normal appears everywhere: it is the limiting distribution of standardized sample means, regardless of the population distribution.

Berry-Esseen Bound (CLT Rate)

The Berry-Esseen theorem quantifies the rate of CLT convergence:

sup⁑z∣P(XΛ‰nβˆ’ΞΌΟƒ/n≀z)βˆ’Ξ¦(z)βˆ£β‰€C⋅ρσ3n\sup_z \left| P\left(\frac{\bar{X}_n - \mu}{\sigma/\sqrt{n}} \leq z\right) - \Phi(z) \right| \leq \frac{C \cdot \rho}{\sigma^3 \sqrt{n}}

where ρ=E[∣Xβˆ’ΞΌβˆ£3]\rho = E[|X - \mu|^3] and CC is a universal constant (best known: C<0.4748C < 0.4748). The convergence rate is O(1/n)O(1/\sqrt{n}).


Relationship to Other Distributions

  • If Z1,Z2,…,ZkZ_1, Z_2, \ldots, Z_k are i.i.d. N(0,1)N(0,1), then Z12+β‹―+Zk2βˆΌΟ‡k2Z_1^2 + \cdots + Z_k^2 \sim \chi^2_k (chi-squared with kk df).
  • The ratio of two independent standard normals follows a Cauchy distribution: Z1/Z2∼Cauchy(0,1)Z_1/Z_2 \sim \text{Cauchy}(0,1).
  • ∣Z∣|Z| follows a half-normal distribution.
  • Z2βˆΌΟ‡12=Gamma(1/2,1/2)Z^2 \sim \chi^2_1 = \text{Gamma}(1/2, 1/2).

Specific Applications

  1. Hypothesis testing β€” The Z-test uses Z=(XΛ‰βˆ’ΞΌ0)/(Οƒ/n)Z = (\bar{X} - \mu_0)/(\sigma/\sqrt{n}) to test H0:ΞΌ=ΞΌ0H_0: \mu = \mu_0 when Οƒ\sigma is known.
  2. Confidence intervals β€” A 100(1βˆ’Ξ±)%100(1-\alpha)\% CI for ΞΌ\mu (known Οƒ\sigma): XΛ‰Β±zΞ±/2β‹…Οƒ/n\bar{X} \pm z_{\alpha/2} \cdot \sigma/\sqrt{n}.
  3. Standardization of data β€” Converting any normal to standard normal for probability calculations.
  4. Quality control β€” Six Sigma methodology uses the standard normal to compute defect rates.

Key Takeaways

Summary: Standard Normal and Z-Table

  • Standard normal: Z∼N(0,1)Z \sim N(0, 1), obtained via Z=(Xβˆ’ΞΌ)/ΟƒZ = (X-\mu)/\sigma
  • PDF: Ο•(z)=12Ο€eβˆ’z2/2\phi(z) = \frac{1}{\sqrt{2\pi}} e^{-z^2/2}; no closed-form CDF
  • Symmetry: Ξ¦(βˆ’z)=1βˆ’Ξ¦(z)\Phi(-z) = 1 - \Phi(z); all odd moments are zero
  • Even moments: E[Z2k]=(2kβˆ’1)!!E[Z^{2k}] = (2k-1)!!; kurtosis =0= 0 (mesokurtic)
  • MGF: MZ(t)=et2/2M_Z(t) = e^{t^2/2}
  • Common critical values: z0.025=1.96z_{0.025} = 1.96 (95%), z0.005=2.576z_{0.005} = 2.576 (99%)
  • Foundation for CLT, z-tests, and confidence intervals when Οƒ\sigma is known
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Standard Normal Distribution and Z-Table

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